Question

Solve:
$9x^2-3x-2=0$

Answer 1

Using the quadratic formula:-

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{3\pm \sqrt{9+72}}{18}$

$x=\frac{3\pm 9}{18}$

so, $x=\frac{3+9}{18}=\frac{12}{18}=\frac{2}{3}$ or $x=\frac{3-9}{18}=\frac{-6}{18}=\frac{-1}{3}$