Solve: $9 x^{4} - 14 x^{2} - 64 = 0$

(x^{2} - 2) (9 x^{2} + 32)

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(x^{2} + 2) (9 x^{2} - 32)

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(x^{2} + 4) (9 x^{2} - 16)

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(x^{2} - 2) (9 x^{2} - 32)

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Solution

The correct option is B $(x^{2} + 2) (9 x^{2} - 32)$
$9 x^{4} - 14 x^{2} - 64$
$= 9 x^{4} - 32 x^{2} + 18 x^{2} - 64$
$= x^{2} (9 x^{2} - 32) + 2 (9 x^{2} - 32)$
$= (x^{2} + 2) (9 x^{2} - 32)$

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(x^{2} - 11 x + 29)^{(x^{2} - 8 x + 7)} = 1

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(x^{2} - 11 x + 29)^{(x^{2} - 8 x + 7)} = 1

x^{2} - 8 x + 16 = 0

x^{2} + 14 x - 32 = 0

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