Solve :

9x + 5 = 4 (x - 2) + 8

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Solution

$9 x + 5 = 4 (x - 2) + 8 \Rightarrow 9 x + 5 = 4 x - 8 + 8 \Rightarrow 9 x - 4 x = - 8 + 8 - 5 \Rightarrow 5 x = - 5 \Rightarrow x = \frac{- 5}{5} = - 1 ∴ x = - 1$

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Similar questions

\frac{9 x - 7}{3 x + 5} = \frac{3 x - 4}{x + 6}

(6 x^{4} + 4 x^{2} + 9 x + 5) \div (2 x + 3)

5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)

{lim}_{x \to 0} \frac{4^{x} - 9^{x}}{x (4^{x} + 9^{x})}

Solve:-

(i) $5 (3 x - 4) - 8 (6 x - 7) = 9 x - 8$

(ii) $2 x - \frac{3 x}{5} = 7$

(iii) $\frac{2 z}{3} - 5 = \frac{3 z}{4} - 1$

(iv) $\frac{4 x}{7} - 12 = 7$

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