Question

Solve:
$9x+99y+98=0$

Answer 1

Consider given the equation,

$9x+99y+98=0$

Put,$x=0$

$9\times 0+99y+98=0$

$y=-\frac{98}{99}$

Put again,$x=1$

$9\times 1+99y+98=0$

$y=-\frac{107}{99}$

Put again,$x=-1$

$9(-1)+99y+98=0$

$y=-\frac{89}{99}$

Hence, this is the answer.