wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve a3(bc)3+b3(ca)3+c3(ab)3

Open in App
Solution

a3(bc)3+b3(ca)3+c3(ab)3

=(abac)3+(bcba)3+(cacb)3

We know that a3+b3+c3=(a+b+c)(a2+b2+c2abbcca)+3abc

=(abac+bcba+cacb)((abac)2+(bcba)2+(cacb)2(abac)(bcba)(bcba)(cacb))
(cacb)(abac)+3(abac)(bcba)(cacb)

=(0)((abac)2+(bcba)2+(cacb)2(abac)(bcba)(bcba)(cacb))
(cacb)(abac)+3(abac)(bcba)(cacb)

=0+3(abac)(bcba)(cacb)

=3(abac)(bcba)(cacb)

=3a(bc)b(ca)c(ab)

=3abc(bc)(ca)(ab)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon