Solve:
$(a - 4) (a - 2) = a^{2} - 8$

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Solution

Given,

$(a - 4) (a - 2) = a^{2} - 8$

$\Rightarrow a^{2} - 6 a + 8 = a^{2} - 8$

$\Rightarrow - 6 a = - 16$

$\Rightarrow a = \frac{8}{3}$ .

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