Solve:
$(a + b)^{2} - a^{2} - b^{2}$ =?

Open in App

Solution

Solution :-
$(a + b)^{2} - a^{2} - b^{2} =$
we have $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
$∴ (a + b)^{2} - a^{2} - b^{2} = a^{2} + b^{2} + 2 a b - a^{2} - b^{2}$
$= 2 a b$

Suggest Corrections

Similar questions

(a^{2} + b^{2} +2ab) - (a^{2} + b^{2} - 2ab)

\frac{a^{2} - b^{2}}{4}

{sin}^{- 1} \frac{a - b}{\sqrt{a^{2} - b^{2}}}

(a^{2} + b^{2}) (- a^{2} + b^{2})

(a - b) x + (a + b) y = a^{2} - 2 a b - b^{2}

(a + b) (x + y) = a^{2} + b^{2}

a (x + y) + b (x - y) = a^{2} - a b + b^{2}

a (x + y) - b (x - y) = a^{2} + a b + b^{2}

Join BYJU'S Learning Program