Question

"Solve:
(a ) <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{2}{3}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{3}{4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{2}$

(b) 4$\frac{2}{3}$ + 3 <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{4}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}-->

Answer 1

(a) $\frac{2}{3}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{3}{4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{2}$
LCM of 3, 4 and 2 = 12

$\frac{2\times 4}{3\times 4}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{3\times 3}{4\times 3}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1\times 6}{2\times 6}$

= $\frac{8}{12}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{9}{12}$ + <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{6}{12}$

= $\frac{8+9+6}{12}$

= $\frac{23}{12}$

(b) 4$\frac{2}{3}$ + 3 <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\frac{1}{4}$

= $\frac{14}{3}$ + $\frac{13}{4}$

LCM of 3 and 4 = 12

$\frac{14\times 4}{3\times 4}$ + $\frac{13\times 3}{4\times 3}$

= $\frac{56}{12}$ + $\frac{39}{12}$

= $\frac{95}{12}$ = 7$\frac{11}{12}$