Solve (ab+1)2 - (ab)2 where, b - a = 1.
a2 + b2
a2 + (b+1)2
(a+1)2 + (b+1)2
b2
(ab+1)2−(ab)2=(a(a+1)+1)2−(a(a+1))2 =(a2(a+1)2+1+2a(a+1))−(a2(a+1)2) =2a(a+1)+1 =2a2+2a+1 =a2+2a+1+a2 =(a+1)2+a2 =b2+a2 [since b=a+1]
If a+b=1 and a−b=7 ;
Find
(i) (a2+b2) (ii) ab
If a,b,c are in G.P., then ___.