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Question

Solve (ab+1)2 - (ab)2
where, b - a = 1


A

a2 + b2

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B

a2 + (b+1)2

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C

(a+1)2 + (b+1)2

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D

b2

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Solution

The correct option is A

a2 + b2


(ab+1)2 - (ab)2
(ab+1)2(ab)2=(a(a+1)+1)2(a(a+1))2 [ b = 1 + a]
=a2×((a+1)2+1+2a(a+1))a2×(a+1)2
=2a2+2a+1
=a2+2a+1+a2
=(a+1)2+a2
=b2+a2


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