Question

Solve and find the additive inverse of the following:
$\left(i\right)\left[\right(-7)\times (-24\left)\right]÷[7-3]$
$\left(ii\right)(-4)+(-18)÷(-4)-3\times (-2)$

Answer 1

i) Given $\left[\right(-7)\times (-24\left)\right]÷[7-3]$
$=168÷4$ (Using BODMAS rule)
= 42
Division of any number by -1 gives the additive inverse of that number. Additive inverse of any integer a is (- a).
So, additive inverse of 42 = - (42) = -42.

(ii) Given: $(-4)+(-18)÷\left[\right(-4)-3\times (-2\left)\right]$
$\left[\right(-4-18\left)\right]÷[-4+6]$ (Using BODMAS rule)
$=-22÷\left[2\right]=-11$
Division of any number by -1 gives the additive inverse of that number. Additive inverse of any integer a is (- a).
So, additive inverse of -11 = - (- 11) = 11.