Solve $b^{2} cos 2 A - a^{2} cos 2 A = b^{2} - a^{2}$

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Solution

$b^{2} cos 2 a - a^{2} cos 2 A = b^{2} - a^{2}$
$\Rightarrow (b^{2} - a^{2}) cos 2 A = b^{2} - a^{2}$
$\Rightarrow cos 2 A = 1$
$∴ 2 A = 2 n π$
$A = n π, n \in I$

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