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Question

Solve:
(b+c)sinA2=acosBC2.

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Solution

b+c=2RsinB+2RsinC=4Rsin(B+C2)cos(BC2)=4RcosA2cosBC2
(b+c)sinA2=2RcosBC2(2sinA2cosA2)=2RcosBC2sinA=acosBC2

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