Solve- b-csinA2-acosB-C2-

b+c=2Rsin B+2Rsin C=4Rsin(B+C2)cos(B C2)=4RcosA2cosB C2 (b+c)sinA2=2RcosB C2(2sinA2cosA2)=2RcosB C2sin A=acosB C2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Allied Angles

Solve: b+csi...

Question

Solve:
$(b + c) sin \frac{A}{2} = a cos \frac{B - C}{2}$ .

Open in App

Solution

Suggest Corrections

Similar questions

a cos (\frac{B - C}{2}) = (b + c) sin \frac{A}{2}

△ A B C

a cos (\frac{B - C}{2}) = (b + c) sin \frac{A}{2}

A B C

cot \frac{A}{2} - cot \frac{B}{2} = \frac{(b - a) s}{Δ}

(b + c) sin \frac{A}{2} = a cos \frac{B - C}{2}

b c {cos}^{2} \frac{A}{2} + c a {cos}^{2} \frac{B}{2} + a b {cos}^{2} \frac{C}{2} = s^{2}

\frac{sin B}{sin C} = \frac{c - a cos B}{b - a cos C}

(b + c) cos \frac{B + C}{2} = a cos \frac{B - C}{2}

Join BYJU'S Learning Program