Solve:
$\begin{matrix} \frac{4}{x} + 3 y = 8 \frac{6}{x} - 4 y = - 5 \end{matrix}$

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Solution

$\frac{4}{x} + 3 y = 8$ ..... equation (1)

$\frac{6}{x} - 4 y = - 5$

$- 4 y = \frac{(- 5 x + 6)}{x} . . . . (2) e q u a t i o n$

$y = \frac{(5 x + 6)}{4}$

Now, substituting value of $y$ is eq $1 s t$
$\frac{4}{x} + 3 (\frac{5 x + 6}{4 x}) = 8$

$\frac{(16 + 15 x + 28)}{4 x} = 8$

$34 + 15 x = 32 x$

$34 = 17 x$

$x = 2$

Now, substituting $x$ in eq (2)
$y = \frac{(5 x + 6)}{4 x}$

$y = \frac{(10 + 6)}{8}$

$y = \frac{16}{8}$

$y = 2$

$∴ x = y = 2$

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