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Question

Solve: ∣ ∣ ∣1+a2b22ab2b2ab1a2+b22a2b2a1a2b2∣ ∣ ∣=(1+a2+b2)3.

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Solution

Now,
∣ ∣ ∣1+a2b22ab2b2ab1a2+b22a2b2a1a2b2∣ ∣ ∣
{R1=R1+bR3 and R2=R2aR1]
=∣ ∣ ∣1+a2+b20b(1+a2+b2)01+a2+b2a(1+a2+b2)2b2a1a2b2∣ ∣ ∣
=(1+a2+b2)2∣ ∣10b01a2b2a1a2b2∣ ∣
=(1+a2+b2)2{1a2b2+2a2b(2b)}
=(1+a2+b2)3.

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