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Toby wants to tile the floor of his room of length 15 ft and width 9 ft. Each square tile has sides of length 1.5 ft

The number of tiles required is

A) 30
B) 45
C) 60
D) 75

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Solution

Dear student,

$N u m b e r o f t i l e s = \frac{A r e a o f f l o o r t o b e t i l e d}{A r e a o f e a c h s q u a r e t i l e} = \frac{l \times b}{a \times a} = \frac{15 \times 9}{1.5 \times 1.5} = \frac{135}{2.25} = \frac{135 \times 100}{225} = \frac{9 \times 100}{15} = 9 \times \frac{20}{3} = 3 \times 20 = 60$

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Solve Toby wants to tile the floor of his room of length 15 ft and width 9 ft. Each square tile has sides of length 1.5 ft The number of tiles required is A) 30 B) 45 C) 60 D) 75

Dear student, Number of tiles=Area of floor to be tiledArea of each square tile=l×ba×a=15×91.5×1.5=1352.25=135×100225=9×10015=9×203=3×20=60 Regards

Solve

Toby wants to tile the floor of his room of length 15 ft and width 9 ft. Each square tile has sides of length 1.5 ft

The number of tiles required is

A) 30
B) 45
C) 60
D) 75