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Q). A sonar echo takes 4.4 s to return from a submarine. If the speed of sound in water is 1500 $m s^{- 1}$ , then the distance of submarine from the sonar is

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Dear student

$T i m e t a k e n b y s o n a r e c h o, t = 4.4 s s p e e d o f s o u n d i n w a t e r i s 1500 m / s l e t t h e d i s \tan c e i s d . 2 d = v \times t \Rightarrow 2 d = 1500 \times 4.4 \Rightarrow d = \frac{1500 \times 4.4}{2} = 1500 \times 2.2 = 3300 m$
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Solve. Q). A sonar echo takes 4.4 s to return from a submarine. If the speed of sound in water is 1500 ms-1, then the distance of submarine from the sonar is

Dear student Time taken by sonar echo, t=4.4sspeed of sound in water is 1500m/slet the distance is d.2d=v×t⇒2d=1500×4.4⇒d=1500×4.42=1500×2.2=3300m Regards

Solve.
Q). A sonar echo takes 4.4 s to return from a submarine. If the speed of sound in water is 1500 $m s^{- 1}$ , then the distance of submarine from the sonar is

Dear student

$T i m e t a k e n b y s o n a r e c h o, t = 4.4 s s p e e d o f s o u n d i n w a t e r i s 1500 m / s l e t t h e d i s \tan c e i s d . 2 d = v \times t \Rightarrow 2 d = 1500 \times 4.4 \Rightarrow d = \frac{1500 \times 4.4}{2} = 1500 \times 2.2 = 3300 m$
Regards