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Question

Solve by cross multiplication method:
6x+7y11=0
5x+2y=13

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Solution

Consider the given equations.

6x+7y11=0

5x+2y13=0

By using cross multiplication, we get

6 7 11

5 2 13


x7×(13)2×(11)=y11×5(13)×6=16×27×5x91+22=y55+78=11235

x69=y23=123

x=3,y=1

Hence, the value of x and y is 3,1.


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