Question

Solve by elimination method:

$3x+2y+25=0$ and $x+y+15=0$

• A. $x=5$ and $y=-20$
• B. $x=3$ and $y=7$
• C. $x=7$ and $y=-9$
• D. $x=1$ and $y=2$

Answer 1

The correct option is A $x=5$ and $y=-20$

Given equations are,

$3x+2y=-25$ ....(1)

and $x+y=-15$ ....(2)

Multiply equation (2) by $2$, we get

$2x+2y=-30$ ....(3)

Subtract equation (1) and (3) to eliminate $y$,

$x=5$

Put this value of $x$ in equation (1), we get

$3\left(5\right)+2y=-25$

$\Rightarrow 15+2y=-25$

$\Rightarrow y=-20$

Therefore, the solution of the given equations are $x=5,y=-20$.