Question

Solve by elimination method $3x+4y=-45,2x-3y=6$.

Answer 1

The given system is
$3x+4y=-25$ (1)
$2x-3y=6$ (2)
To eliminate the variable x, let us multiply (1) by 2 and (2) by -3 to obtain
$\left(1\right)\times 2\to 6x+8y=-50$ (3)
$\left(2\right)\times -3\to -6x+9y=-18$ (4)
Now, adding (3) and (4) we get, y 17 = 68 which gives y = 4 Next, substitute y y = - 4 in (1) to obtain
$3x+(-4)=-25$
That is, $x=-3$
Hence, the solution is ( -3, -4 ).