Solve by using substitution method. 3x+4y=10 & 2x−2y=2
3x+4y=10 .....(1)
2x−2y=2 .....(2)
equation (2) can be written as
⇒x−y=1
⇒x=y+1 .....(3)
substitute x value in equation (2)
⇒3x+4y=10
⇒3(y+1)+4y=10
⇒3y+3+4y=10
⇒7y=7
⇒y=1
then, substitute y value in equation (3)
⇒x=y+1=1+1=2
∴x=2,y=1