Question

Solve:
$\frac{\sin \theta .\sec ({90}^o-\theta )\cos ({90}^o-\theta )}{\csc ({90}^o-\theta ).\cos ({90}^o-\theta ).\tan ({90}^o-\theta )}-\frac{\tan ({90}^o-\theta )}{\cot \theta }=0$

Answer 1

$\frac{\sin \theta \sec (90°-\theta )\cos (90°-\theta )}{\csc (90°-\theta )\cos (90°-\theta )\tan (90°-\theta )}-\frac{\cot \theta }{\cot \theta }$

$=\frac{\sin \theta \csc \theta }{\cot \theta \tan \theta }-1$

$=1-1$

$=0.$

Hence, the answer is $0.$