Question

Solve: $\frac{x}{3}-\frac{y}{2}=1,\frac{x}{4}+y=3\frac{1}{2}$

• A. $4,1$
• B. $8,\frac{1}{2}$
• C. $6,2$
• D. $3,2$

Answer 1

The correct option is C $6,2$

Given equations are
$\frac{x}{3}-\frac{y}{2}=1$ --- (1)
And $\frac{x}{4}+y=3\frac{1}{2}$ --- (2)

Multiplying equation $\left(1\right)$ with $2$ we get, $\frac{2x}{3}-y=2$ ----- equation $\left(3\right)$

Adding equation $\left(2\right)$ and
$\left(3\right)$, we get $\frac{11x}{12}=\frac{11}{2}=>x=6$

Substituting $x=6$
in the equation $\left(1\right)$, we get $\frac{6}{3}-\frac{y}{2}=1=>\frac{y}{2}=1=>y=2$