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Byju's Answer
Standard XII
Mathematics
Domain and Range of Basic Inverse Trigonometric Functions
Solve : cos...
Question
Solve :
cos
27
o
+
cos
93
o
+
cos
147
o
Open in App
Solution
cos
27
o
+
cos
93
o
+
cos
147
o
⇒
2
cos
(
27
o
+
93
2
)
cos
(
27
−
93
2
)
+
cos
147
o
⇒
cos
C
+
cos
D
=
2
cos
(
C
+
D
2
)
cos
(
C
−
D
2
)
⟶
(
1
)
⇒
2
cos
(
60
o
)
cos
(
33
o
)
+
cos
147
o
∵
cos
60
o
=
1
2
⇒
cos
33
o
+
cos
147
o
Again, using
1
⇒
2
cos
(
33
+
147
2
)
cos
(
33
−
147
2
)
⇒
2
cos
(
90
o
)
cos
(
−
57
o
)
=
0
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