wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Solve : cotθ+cosecθ=3 for values of θ between 0 & 360.

A
30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
60
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
180
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 60
cotθ+cosecθ=3cotθ2=3θ2=nπ+π6θ=2nπ+π3
For θϵ(0o,360o)
θ=60o

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Continuity of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon