1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Continuity of a Function
Solve : θ +...
Question
Solve :
cot
θ
+
c
o
s
e
c
θ
=
√
3
for values of
θ
between
0
∘
&
360
∘
.
A
30
∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
60
∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
120
∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
180
∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
60
∘
cot
θ
+
c
o
s
e
c
θ
=
√
3
⇒
cot
θ
2
=
√
3
⇒
θ
2
=
n
π
+
π
6
⇒
θ
=
2
n
π
+
π
3
For
θ
ϵ
(
0
o
,
360
o
)
⇒
θ
=
60
o
Suggest Corrections
0
Similar questions
Q.
If
c
o
s
e
c
θ
−
c
o
t
θ
=
1
3
,
the value of
(
c
o
s
e
c
θ
+
c
o
t
θ
)
is:
Q.
Prove that
t
a
n
(
90
−
θ
)
c
o
s
e
c
θ
+
1
+
c
o
s
e
c
θ
+
1
c
o
t
θ
=
2
s
e
c
θ
Q.
7. Classes 0-30 30-60 60-90 90-120 120-150 150-180 180-210Frequencies 23510
Q.
Solve :
(
c
o
s
e
c
θ
−
c
o
t
θ
)
√
1
+
c
o
s
θ
1
−
c
o
s
θ
=
1
Q.
The value of
cosec
θ
+
sec
(
270
°
−
θ
)
−
cosec
(
270
°
+
θ
)
+
sec
(
180
°
−
θ
)
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Continuity of a Function
MATHEMATICS
Watch in App
Explore more
Continuity of a Function
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app