Question

Solve:
${\csc }^2\theta \cdot {\tan }^2\theta -1={\tan }^2\theta$

Answer 1

L.H.S

$cs{c}^2\theta \cdot ta{n}^2\theta -1$

$={\sec }^2\theta -1$

$={\tan }^2\theta$

R.H.S

Hence, proved.