Solve D - - - 1 - 2 1- 2 1 - 1- 1 3 1 -

D = | [ 1 amp; 2 amp; 1; 2 amp; 1 amp; 1; 1 amp; 3 amp; 1 ]] D= 1(1+3)+2(2+1)+1(6 1) D = 4+6+5 = 15 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of a Determinant

Solve D = |...

Question

Solve $D = ∣ ∣ ∣ ∣ \begin{matrix} 1 & - 2 & 1 2 & 1 & - 1 1 & 3 & 1 \end{matrix} ⎤ ⎥ ⎦$

Open in App

Solution

Suggest Corrections

Similar questions

A = [\begin{matrix} 2 & 1 2 & 1 \end{matrix}] .

X

A X = A .

[\begin{matrix} x & 0 1 & y \end{matrix}] - [\begin{matrix} 2 & - 4 - 3 & - 4 \end{matrix}] = [\begin{matrix} 3 & 5 6 & 3 \end{matrix}] - [\begin{matrix} 2 & 1 2 & 1 \end{matrix}],

x =

y =

A = [\begin{matrix} 2 & 1 2 & 1 \end{matrix}]

2

X

X A = I

(D^{2} + D + 1)^{2} (D - 2) y = 0

\frac{d y}{d x} = 1 + \frac{1}{y^{2}}

Join BYJU'S Learning Program