Question

Solve:

$\frac{1}{3}{x}^2-2x-9$.

Answer 1

Given $\frac{1}{3}{x}^2-2x-9$

Since we know quadratic form of an equation is $a{x}^2+bx+c=0$

Let us solve the given equation

$\frac{1}{3}{x}^2-2x-9=0$

$\Rightarrow$ $\frac{x^2-6x-27}{3}=0$

$\Rightarrow$ $x^2-6x-27=0$

$\Rightarrow$ $x^2+3x-9x-27=0$

$\Rightarrow$ $x(x+3)-9(x+3)=0$

$\Rightarrow (x-9)(x-3)=0$

$\Rightarrow$ $(x-9)=0;(x+3)=0$

$\Rightarrow$ $x=9;x=-3$

$\therefore$ $x=9,-3$