Question

Solve:
$\frac{1}{5}\left(\frac{1}{3x}-5\right)=\frac{1}{3}\left(3-\frac{1}{x}\right)$

Answer 1

$\frac{1}{5}(\frac{1}{3x}-5)$ $=$ $\frac{1}{3}(3-\frac{1}{x})$

$\frac{1}{15x}-1=1-\frac{1}{3x}$

$Multiplying$ $both$ $sides$ $by$ $15x,$

$1-15x=15x-5$

$30x=6$

$x=\frac{1}{5}$