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Byju's Answer
Standard VIII
Mathematics
Terms
Solve: 11a2...
Question
Solve:
11
a
2
+
9
a
c
11
b
2
+
9
b
d
=
a
2
+
3
a
c
b
2
+
3
b
d
Open in App
Solution
11
a
2
+
9
a
c
11
b
2
+
9
b
d
=
a
2
+
3
a
c
b
2
+
3
b
d
a
(
11
a
+
9
c
)
b
(
11
b
+
9
d
)
=
a
(
a
+
3
c
)
b
(
b
+
3
d
)
(
11
a
+
9
c
)
(
b
+
3
d
)
=
(
a
+
3
c
)
(
11
b
+
9
d
)
11
a
b
+
33
a
d
+
9
c
b
+
27
c
d
=
11
a
b
+
9
a
d
+
33
b
c
+
27
c
d
33
a
d
−
9
a
d
+
9
c
b
−
33
b
c
=
0
24
a
d
−
24
b
c
=
0
24
(
a
d
−
b
c
)
=
0
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1
Similar questions
Q.
If a, b, c, d are in proportion then prove that
11
a
2
+
9
a
c
11
b
2
+
9
b
d
=
a
2
+
3
a
c
b
2
+
3
b
d
Q.
If a, b, c, d are in proportion , then prove that
(i)
11
a
2
+
9
a
c
11
b
2
+
9
b
d
=
a
2
+
3
a
c
b
2
+
3
b
d
(ii)
a
2
+
5
c
2
b
2
+
5
d
2
=
a
b
(iii)
a
2
+
a
b
+
b
2
a
2
-
a
b
+
b
2
=
c
2
+
c
d
+
d
2
c
2
-
c
d
+
d
2
Q.
If a+b+c=0 then prove that, [(b+c)²/3bc]+[(c+a)²/3ac]+[(a+b)²/3ac]
Q.
Solve:
(
a
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+
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)
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(
a
2
+
b
2
- 2ab
)
Q.
Solve:
a
2
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b
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4
sin
−
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a
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√
a
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