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Question

Solve: 11a2+9ac11b2+9bd=a2+3acb2+3bd

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Solution

11a2+9ac11b2+9bd=a2+3acb2+3bd

a(11a+9c)b(11b+9d)=a(a+3c)b(b+3d)

(11a+9c)(b+3d)=(a+3c)(11b+9d)

11ab+33ad+9cb+27cd=11ab+9ad+33bc+27cd

33ad9ad+9cb33bc=0

24ad24bc=0

24(adbc)=0

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