Question

Solve $\frac{2^3\times 3^5\times 8}{27\times 36}$.

Answer 1

We have,

$\frac{2^3\times 3^5\times 8}{27\times 36}$

$=\frac{2^3\times 3^5\times 8}{3^3\times 6^2}$

$=\frac{2^3\times 3^2\times 8}{(2\times 3{)}^2}$

$=\frac{2^3\times 3^2\times 8}{2^2\times 3^2}$

$=2\times 8$

$=16$

Hence, this is the answer.