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Algebra of Limits

Solve : 2+3x...

Question

Solve :
$\frac{2 + 3 x}{2 - 3 x} + \frac{3 + 2 x}{3 - 2 x} = 0$

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Solution

$\frac{2 + 3 x}{2 - 3 x} + \frac{3 + 2 x}{3 - 2 x} = 0 (2 + 3 x) (2 - 3 x) + (3 + 2 x) (3 - 2 x) = 0 4 - 9 x^{2} + 9 - 4 x^{2} = 0 13 - 13 x^{2} = 0 x^{2} = 1 x = \pm 1$

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