Solve - 25 x - 10 - 2x - 3-

The correct option is B 58 Given, 25 ( x+10 )=2x+3 ⇒ 2x+205=2x+31 #160; #160; #160;...[By Distribution Law]By Cross multiplying, ...

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Standard VIII

Mathematics

Solving Equations with Variables on Both Sides

Solve : 25 ...

Question

Solve : $\frac{2}{5} (x + 10) = 2 x + 3$ .

\frac{1}{5}

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\frac{5}{8}

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\frac{5}{4}

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\frac{3}{8}

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Solution

The correct option is B $\frac{5}{8}$
Given, $\frac{2}{5} (x + 10) = 2 x + 3$

$\Rightarrow$ $\frac{2 x + 20}{5} = \frac{2 x + 3}{1}$ ...[By Distribution Law]

By Cross-multiplying, we get,

$\Rightarrow$ $2 x + 20 = 5 \times (2 x + 3)$

$\Rightarrow$ $2 x + 20 = 10 x + 15$ ...[By Distribution Law].

Transposing $x$ terms to one side, we get,
$\Rightarrow$ $2 x - 10 x = 15 - 20$

$\Rightarrow$ $- 8 x = - 5$

$\Rightarrow 8 x = 5$

$\Rightarrow$ $x = \frac{5}{8}$ .

Hence, option $B$ is correct.

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Similar questions

Solve the following:
(a) $5 x + 8 = 23$ (b) $2 y - 4 = - 8$ (c) $2 (t + 1) + 15 = 3$ (d) $- y + 46 = 32$ (e) $2 x + 3 = 3$

Q. Solve:

\frac{2 x + 7}{5} - \frac{3 x + 11}{2} = \frac{2 x + 8}{3} - \frac{5}{1}

Q. Solve:

∣ ∣ ∣ ∣ \begin{matrix} 3 x + 4 & x + 2 & 2 x + 3 4 x + 5 & 2 x + 3 & 3 x + 4 10 x + 17 & 3 x + 5 & 5 x + 8 \end{matrix} ∣ ∣ ∣ ∣ = 0

. The value of the determinant at

x = - 1

is:

Q. Solve:

\sqrt[3]{4^{0} + \frac{3}{5}} = {(\frac{5}{8})}^{1 - 2 x}

Find x, if

$(i) {(\frac{1}{4})}^{- 4} \times {(\frac{1}{4})}^{- 8} = {(\frac{1}{4})}^{- 4 x} (i i) {(\frac{- 1}{2})}^{- 19} \div {(\frac{- 1}{2})}^{8} = {(\frac{- 1}{2})}^{- 2 x + 1} (i i i) {(\frac{3}{2})}^{- 3} \div {(\frac{3}{2})}^{5} = {(\frac{3}{2})}^{2 x + 1} (i v) {(\frac{2}{5})}^{- 3} \times {(\frac{2}{5})}^{15} = {(\frac{2}{5})}^{2 + 3 x} (v) {(\frac{5}{4})}^{- x} \div {(\frac{5}{4})}^{- 4} = {(\frac{5}{4})}^{5} (v i) {(\frac{8}{3})}^{2 x + 1} \times {(\frac{8}{3})}^{5} = {(\frac{8}{3})}^{x + 2}$

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Solve : 25(x+10)=2x+3.

The correct option is B 58Given, 25(x+10)=2x+3⇒ 2x+205=2x+31 ...[By Distribution Law]By Cross-multiplying, we get,⇒ 2x+20=5×(2x+3)⇒ 2x+20=10x+15 ...[By Distribution Law].Transposing x terms to one side, we get,⇒ 2x−10x=15−20⇒ −8x=−5⇒8x=5⇒ x=58.Hence, option B is correct.

Solve : $\frac{2}{5} (x + 10) = 2 x + 3$ .