Solve- 2m-2-32m-n6m-3m-n-1

2^m+2,3^2m n/6^m.3^m n 1 = 2^m+2.3^2m n/(2× 3)^m.3^m n 1 2^m+2,3^2m n/2^m,3^m3^m n 1 = #160; 2^m.4.3^2m n/2^m.3^2m n 1 = 4.3.3^2m n 2n+n ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Expansion of (a ± b ± c)²

Solve: 2m+2....

Question

Solve:
$\frac{2^{m + 2} {.3}^{2 m - n}}{6^{m} {.3}^{m - n - 1}}$

Open in App

Solution

Suggest Corrections

Similar questions

{lim}_{n \to} {[\frac{(n + 1) (n + 2), . . ., 3 n}{n^{2 m}}]}^{1 / n}

(6 m - n) (36 m^{2} + 6 m n + n^{2}) - (3 m + 2 n)^{3}

\frac{2^{m + 1} \times 3^{2 m - n} \times 5^{m + n} \times 6^{n}}{6^{m} \times 10^{n + 2} \times 15^{m}}

\frac{2^{m + 3} \times 3^{2 m - n} \times 5^{m + n + 3} 6^{n + 1}}{6^{m + 1} \times 10^{n + 3} \times 15^{m}}

(2 m^{3} + 3 m) (5 m - 1) = 0

Join BYJU'S Learning Program