Solve- 2m-2-32m-n6m-3m-n-1

2^m+2,3^2m n/6^m.3^m n 1 = 2^m+2.3^2m n/(2× 3)^m.3^m n 1 2^m+2,3^2m n/2^m,3^m3^m n 1 = #160; 2^m.4.3^2m n/2^m.3^2m n 1 = 4.3.3^2m n 2n+n ...

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Expansion of (a ± b ± c)²

Solve: 2m+2....

Question

Solve:
$\frac{2^{m + 2} {.3}^{2 m - n}}{6^{m} {.3}^{m - n - 1}}$

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Solution

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