Question

Solve: $\frac{(2-m{)}^2}{m}=1$.

Answer 1

Now,

$\frac{(2-m{)}^2}{m}=1$

or, $(2-m{)}^2=m$

or, $m^2-4m+4=m$

or, $m^2-5m+4=0$

or, $(m-4)(m-1)=0$

or, $m=4,1$.