Question

Solve:
$\frac{2y-5}{3y+1}=\frac{3}{13}$

Answer 1

$\frac{2y-5}{3y+1}=\frac{3}{13}$

$13(2y-5)=3(3y+1)$

By cross Multiplication

$26y-65=9y+3$

$26y-9y=65+3$

$17y=68$

$y=\frac{68}{17}\Rightarrow y=4$