Question

Solve:
$\frac{3}{(2x-1)}+\frac{4}{(2x+1)}=\frac{7}{2x}$

Answer 1

$\frac{3}{(2x-1)}+\frac{4}{(2x+1)}=\frac{7}{2x}$

$\Rightarrow$ $\frac{3(2x+1)+4(2x-1)}{(2x-1)(2x+1)}=\frac{7}{2x}$

$\Rightarrow$ $\frac{6x+3+8x-4}{(2x{)}^2-(1{)}^2}=\frac{7}{2x}$

$\Rightarrow$ $\frac{14x-1}{4x^2-1}=\frac{7}{2x}$

$\Rightarrow$ $2x(14x-1)=7(4x^2-1)$

$\Rightarrow$ $28x^2-2x=28x^2-7$

$\Rightarrow$ $2x=7$

$\therefore$ $x=\frac{7}{2}$