Question

Solve:

$\frac{(-3{)}^3\times (-2{)}^5\times 7^2}{(-1{)}^5\times (-7{)}^2\times 2^5}$

Answer 1

$\frac{{(-3)}^3\ast {(-2)}^5\ast 7^2}{{(-1)}^5\ast {(-7)}^2\ast 2^5}=\frac{(-3\ast -3\ast -3)\times (-2\ast -2\ast -2\ast -2\ast -2)\times (7\ast 7)}{(-1\ast -1\ast -1\ast -1\ast -1)\times (-7\ast -7)\times (2\ast 2\ast 2\ast 2\ast 2)}$

$=\frac{(-27)\ast (-32)\ast \left(49\right)}{(-1)\ast 49\ast 32}=-27$