Question

Solve :$\frac{(3^5{)}^2\times 7^3}{(3^3{)}^3\times 7^2}$

Answer 1

Laws of indices:
$(a^m{)}^n=a^{mn}$
$\frac{a^m}{a^n}=a^{m-n}$
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$\frac{(3^5{)}^2\times 7^3}{(3^3{)}^3\times 7^2}$
$=\frac{3^{10}\times 7^3}{3^9\times 7^2}$
$=3^{10-9}\times 7^{3-2}$
$=3\times 7$
$=21$