Question

Solve:
$\frac{(32{)}^{\frac{2}{5}}\times (4{)}^{-\frac{1}{2}}\times (8{)}^{\frac{1}{3}}}{2^{-2}+(64{)}^{-1/3}}$

Answer 1

$\frac{(32{)}^{\frac{2}{5}}\times (4{)}^{-\frac{1}{2}}\times (8{)}^{\frac{1}{3}}}{2^{-2}+(64{)}^{-1/3}}=\frac{(2^5{)}^{\frac{2}{5}}\times (2^2{)}^{-\frac{1}{2}}\times (2^3{)}^{\frac{1}{3}}}{2^{-2}+(4^3{)}^{-\frac{1}{3}}}=\frac{2^2\times 2^{-1}\times 2}{\frac{1}{4}+\frac{1}{4}}=\frac{4}{\frac{1}{2}}=8$