Question

solve:
$\frac{3t-2}{3}+\frac{2t+3}{2}=t+\frac{7}{6}$

Answer 1

$\frac{3t-2}{3}+\frac{2t+3}{2}=t+\frac{7}{6}$

$\Rightarrow \frac{6t-4+6t+9}{6}-t=\frac{7}{6}$

$\Rightarrow \frac{12t+5-6t}{6}=\frac{7}{6}$

$\Rightarrow 6t+5=7$

$\Rightarrow 6t=7-5=2$

$\Rightarrow t=\frac{2}{6}=\frac{1}{3}$

$\therefore t=\frac{1}{3}$