Question

Solve $\frac{3t-2}{3}+\frac{2t+3}{2}=t+\frac{7}{6}$

Answer 1

We have $\frac{3t-2}{3}+\frac{2t+3}{2}=t+\frac{7}{6}$

$\Rightarrow \frac{2(3t-2)+3(2t+3)}{6}=\frac{6t+7}{6}$

$\Rightarrow 6t-4+6t+9=6t+7$

$\Rightarrow 6t+5=7$

$\Rightarrow 6t=7-5$

$\Rightarrow 6t=2$

$\Rightarrow t=\frac{2}{6}$

$\therefore t=\frac{1}{3}$