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Byju's Answer
Standard VIII
Mathematics
Multiplication of Any Polynomial
Solve: 3x+1...
Question
Solve:
3
x
+
1
2
−
4
x
−
1
=
x
+
2
Open in App
Solution
3
x
+
1
2
−
4
x
−
1
=
x
+
2
⇒
(
3
x
+
1
)
(
x
−
1
)
−
8
2
(
x
−
1
)
=
x
+
2
⇒
(
3
x
+
1
)
(
x
−
1
)
−
8
=
2
(
x
+
2
)
(
x
−
1
)
⇒
3
x
2
−
3
x
+
x
−
1
−
8
=
2
[
x
2
−
x
+
2
x
−
2
]
⇒
3
x
2
−
2
x
−
9
=
2
x
2
−
2
x
+
4
x
−
4
⇒
3
x
2
−
2
x
−
9
=
2
x
2
+
2
x
−
4
⇒
3
x
2
−
2
x
−
9
−
2
x
2
−
2
x
+
4
=
0
⇒
x
2
−
4
x
−
5
=
0
⇒
x
2
−
5
x
+
x
−
5
=
0
⇒
x
(
x
−
5
)
+
1
(
x
−
5
)
=
0
⇒
(
x
−
5
)
(
x
+
1
)
=
0
∴
x
=
5
,
−
1
Suggest Corrections
0
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Q.
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