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Question

Solve: 4π×107×20×0.5×(0.1)22[(0.1)2+(0.1)2]3/2

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Solution

y=4π×107×20×0.5×(0.1)22[(0.1)2+(0.1)2]3/2=4×π×2×106×5×101×1×1022[0.01+0.01]3/2=20×π×1092[0.02]3/2=2×π×108[2×102]3/2=2×π×10823/2×103=2×π×108(2)3×103=2×π×105(2)3=2×π×10522=π2×105

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