Solve- 5x-4-1x-1-3x2-3x-4

The correct option is A 32 #160; 5x 4 1x+1=3x^2 3x 4 #160; 5x 4 1x+1=3x^2 4x+x 4 #160; 5x 4 1x+1=3x(x 4)+1(x 4) #160; 5x 4 1x+ ...

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Byju's Answer

Standard XII

Mathematics

Inequalities Involving Modulus Function

Solve: 5x-4...

Question

Solve: $\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{x^{2} - 3 x - 4}$

\frac{- 3}{2}

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\frac{3}{2}

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\frac{- 3}{4}

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None of these

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Solution

The correct option is A $\frac{- 3}{2}$
$\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{x^{2} - 3 x - 4}$

$\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{x^{2} - 4 x + x - 4}$

$\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{x (x - 4) + 1 (x - 4)}$

$\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{(x + 1) (x - 4)}$

$\frac{5 (x + 1)}{(x - 4) (x + 1)} - \frac{1 (x - 4)}{(x + 1) (x - 4)} = \frac{3}{(x - 4) (x + 1)}$

$5 x + 5 - (x - 4) = 3$

$5 x + 5 - x + 4 = 3$

$4 x = - 6$

$x = - \frac{3}{2}$

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Similar questions

Q. Solve the following equations:
a)

5 (3 - x) - 2 (4 - 3 x) = 11 - 2 (x - 1)

6 - 4 (x + 3) = 2 (x - 1)

5 (1 - 2 x) + 2 (3 - x) = 3 (x + 4) + 14

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve the following linear equations.

2 (3 - 2 x) = 13

\frac{x}{2} = 5 + \frac{x}{3}

7 (x - 2) = 2 (2 x - 4)

3 x - \frac{1}{3} = 2 (x - \frac{1}{2}) + 5

Q. Solve:

\frac{2 x - 1}{3} \geq \frac{3 x - 2}{4} - \frac{2 - x}{5}

Q. Solve

x + 2) ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 2 x^{3} - 4 x^{2} - 3 x - 1

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Solve: 5x−4−1x+1=3x2−3x−4

The correct option is A −32 5x−4−1x+1=3x2−3x−4 5x−4−1x+1=3x2−4x+x−4 5x−4−1x+1=3x(x−4)+1(x−4) 5x−4−1x+1=3(x+1)(x−4) 5(x+1)(x−4)(x+1)−1(x−4)(x+1)(x−4)=3(x−4)(x+1)5x+5−(x−4)=35x+5−x+4=34x=−6x=−32

Solve: $\frac{5}{x - 4} - \frac{1}{x + 1} = \frac{3}{x^{2} - 3 x - 4}$