Solve- 9n-32-3n - 27n33m-23 - 12

Since there is no exponential term of 3 in R.H.S. #160; 9^n_× 3^2_× 3^n_ 27^n_3^3m_ = 3^0_ = 1 = gt; 3^2n+2+n_ 3^3n_3^3m_× 8 = gt; 3^3n 3m ...

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Properties of Iota

Solve: 9n×3...

Question

Solve: $\frac{9^{n} \times 3^{2} \times 3^{n} - 27^{n}}{3^{3 m} \times 2^{3}} = \frac{1}{2}$

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Solution

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Similar questions

\frac{9^{n} \times 3^{2} \times 3^{n} - (27)^{n}}{3^{3 m} \times 2^{3}} = 3^{- 3}

(m - n) = 1

\frac{9^{n} \times 3^{2} \times (3 \frac{n}{2}) - (27)^{n}}{3^{3 m} \times 2^{3}} = \frac{1}{27}

\frac{9^{n} \times 3^{2} \times {(3^{- n / 2})}^{- 2} - {(27)}^{n}}{3^{3 m} \times 2^{3}} = \frac{1}{27}

m - n = 1

\frac{9^{n} \times 3^{2} \times (3^{- n / 2})^{- 2} - (27)^{n}}{3^{3 m} \times 2^{3}}

\frac{1}{27}

\frac{9^{n} \times 3^{2} \times {(3}^{- \frac{n}{2}})^{- 2} - 27^{n}}{3^{3 m} \times 2^{3}} = \frac{1}{27}

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