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a3275a216a+3÷a2+3a+a25a21

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Solution

a3275a216a+3÷a2+3a+225a21
=a3275a216a+3×25a21a2+3a+9
=(a3)(a2+3a+9)(5a1)(a3)×(5a+1)(5a1)(a2+3a+9)
=(5a+1)

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