wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve:
cb cos Abc cos A=cos Acos C

Open in App
Solution

Given, cbcosAbccosA=cosAcosC

c(b2+c2a22c)b(b2+c2a22b)=b2+c2a22bcb2+c2a22ab (cosine rule)

a2+c2b22ca2+b2c22b=b2+c2a22bca2+b2c22ab

ba2+bc2b3=ab2+ac2a3

ab(ab)+c2(ba)+a3b3=0

(ab)[ab+(c2)+a2+b2+ab]=0

a=b.....................................(1)

or a2+b2+2ab=c2

(a+b)2=c2 [ a+b+c0]

a+b=c................................(2)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle and Its Measurement
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon