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Question

Solve:
cosA1+sinA+1+sinAcosA =2secA

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Solution

Consider the L.H.S.

=cosA1+sinA+1+sinAcosA

=cos2A+(1+sinA)2cosA(1+sinA)

=cos2A+1+sin2A+2sinAcosA(1+sinA)

=1+cos2A+sin2A+2sinAcosA(1+sinA)

=1+1+2sinAcosA(1+sinA)

=2(1+sinA)cosA(1+sinA)

=2cosA=2secA

Hence proved.


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