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Question

Solve:
d2ydx2+3dydx54y=0.

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Solution

Given the differential equation,
d2ydx2+3dydx54y=0.......(1).
Let y=cemx for c0 be a trial solution of equation (1).
Then the auxiliary equation is
m2+3m54=0
or, m2+9m6m54=0
or, (m+9)(m6)=0.
or, m=6,9.
So the solution is y=c1e9x+c2e6x. [ Where c1 and c2 are arbitrary constant.]

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